In a fechral spiral 6 m long and with a cross-section of 0.2 m2, a current flows, the current in the spiral is 1.5 A. Find the resistance of the spiral, the voltage at its ends, the current power, the work of the current in 8 hours? (p = 1.2 * 10 (minus 6 degrees) Ohm * m)
Data: l – length of the taken fechral spiral (l = 6 m); S – section of the spiral (S = 0.2 mm2 (S = 0.2 m2 too large section for the spiral)); I – current (I = 1.5 A); t – elapsed time (t = 8 h = 28.8 * 10 ^ 3 s).
Const: ρph – beats. electrical resistance of Fehrali (according to the condition ρf = 1.2 * 10 ^ -6 Ohm * m = 1.2 Ohm * mm2 / m).
1) Resistance of the spiral: R = ρph * l / S = 1.2 * 6 / 0.2 = 36 Ohm.
2) The voltage at the ends of the taken fechral spiral: U = I * R = 1.5 * 36 = 54 V.
3) Current power: P = I2 * R = U * I = 54 * 1.5 = 81 W.
4) Work current: A = U * I * t = P * t = 81 * 28.8 * 10 ^ 3 = 2332.8 * 10 ^ 3 W ≈ 2.33 MW.
Answer: The resistance of the taken fechral spiral is 36 ohms, the voltage at the ends is 54 W, the current power is 81 W, the current work for 8 hours is 2.33 MW.
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