In a flashlight lamp at a voltage of 4.5 V, the current is 0.36 A. Determine the resistance of the lamp
August 3, 2021 | education
| In a flashlight lamp at a voltage of 4.5 V, the current is 0.36 A. Determine the resistance of the lamp coil when it is hot.
Given:
U = 4.5 Volts – voltage in the flashlight lamp;
I = 0.36 Ampere – amperage in a flashlight lamp.
It is required to determine R (Ohm) – the resistance of the coil of the flashlight lamp.
To determine the coil resistance of a flashlight lamp, you must use the following formula (Ohm’s law):
U = I * R, hence:
R = U / I = 4.5 / 0.36 = 12.5 ohms.
Answer: The coil resistance of the flashlight lamp is 12.5 ohms.
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