In a flask, 25 g of a 2% solution of silver nitrate AgN03, 15 g of a 3% solution of silver nitrate AgN03

| May 4, 2021 | education

In a flask, 25 g of a 2% solution of silver nitrate AgN03, 15 g of a 3% solution of silver nitrate AgN03, 20 g of 10% sodium nitrate NaN03, 30 g of a 20% solution of sodium nitrate NaN03 and 10 g of water were mixed. Calculate the mass fraction of sodium nitrate and the mass fraction of silver nitrate in the resulting solution.

1. Calculate the masses of silver nitrate in the first and second solutions:

m1 (AgNO3) = w1 (AgNO3) * m1 (solution AgNO3) = 0.02 * 25 = 0.5 g;

m2 (AgNO3) = w2 (AgNO3) * m2 (AgNO3 solution) = 0.03 * 15 = 0.45 g;

2.Calculate the mass of sodium nitrate in two of its solutions:

m1 (NaNO3) = w1 (NaNO3) * m1 (solution NaNO3) = 0.1 * 20 = 2 g;

m2 (NaNO3) = w2 (NaNO3) * m2 (solution NaNO3) = 0.2 * 30 = 6 g;

3. find the total masses of salts and the resulting solution:

mtot (AgNO3) = m1 (AgNO3) + m2 (AgNO3) = 0.5 + 0.45 = 0.95 g;

mtot (NaNO3) = m1 (NaNO3) + m2 (NaNO3) = 2 + 6 = 8 g;

mpol (solution) = m1 (solution AgNO3) + m2 (solution AgNO3) + m1 (solution NaNO3) + m2 (solution NaNO3) + m (H2O) = 25 + 15 + 20 + 30 + 10 = 100 g;

4.determine the mass fraction of salts in the resulting solution:

w (AgNO3) = mtotal (AgNO3): mpol (solution) = 0.95: 100 = 0.0095 or 0.95%;

w (NaNO3) = mtot (NaNO3): mpol (solution) = 8: 100 = 0.08 or 8%.

Answer: 0.95% AgNO3, 8% NaNO3.



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