In a household electric stove, designed for a voltage of 220 V, there are two spirals with a resistance

| September 17, 2021 | education

In a household electric stove, designed for a voltage of 220 V, there are two spirals with a resistance of 55 Ohms. What is the electric power of the tile when one spiral is turned on; two spirals in succession; two spirals in parallel?

U = 220 V.

R = 55 ohms.

N -?

Npos -?

Npair -?

The current power N is determined by the formula: N = U ^ 2 / R, where U is the voltage at the ends of the spiral, R is the resistance of the spiral.

N = (220V) ^ 2/55 Ohm = 880 W.

When the conductors are connected in series, the total electric stove will be the sum: Rpos = R + R = 2 * R.

Npos = U ^ 2/2 * R.

Npos = (220 V) ^ 2/2 * 55 Ohm = 440 W.

With parallel connection of the spirals, the total resistance of the electric stove Rpair will be determined by the formula: Rpair = R * R / (R + R) = R / 2.

Npair = 2 * U ^ 2 / R.

Npair = 2 * (220 V) ^ 2/55 Ohm = 1760 Ohm.

Answer: N = 880 W, Npos = 440 W, Npar = 1760 Ohm.



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