In a hydraulic machine, a pressure of 2N / cm2 was applied to the small piston.

| February 28, 2021 | education

In a hydraulic machine, a pressure of 2N / cm2 was applied to the small piston. What force will act on a large piston if its area is 20 cm2? What property of liquids is the structure of a hydraulic machine based on?

Given:

P = 20 N / cm2 – pressure applied to the small piston of the hydraulic machine;

S = 20 square centimeters – the area of ​​the large piston of the hydraulic machine.

It is required to determine F (Newton) – the force acting on the large piston of the hydraulic machine.

According to the laws of hydraulics, the fluid pressure in the system of small and large pistons will be the same. Then, the force acting on the large piston can be found from the formula:

P = F / S, from this we find that

F = P * S = 20 * 20 = 400 Newtons.

Answer: A force equal to 400 Newtons will act on the large piston of the hydraulic machine.



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