# In a hydraulic press, a force of 10N acts on a small piston with an area of 1 cm2. What is the force acting

In a hydraulic press, a force of 10N acts on a small piston with an area of 1 cm2. What is the force acting on a large piston with an area of 0.1 m2?

Sm = 1 cm2 = 0.0001 m2.

Fm = 10 N.

Sb = 0.1 m2.

Fb -?

The work of a hydraulic press is based on Pascal’s law, according to which the fluid pressure is transmitted in all directions in the same way. The fluid pressure on the small Pm and the large piston Pb are equal to each other: Pm = Pb.

The pressure on the corresponding pistons is expressed by the formulas: Pm = Fm / Sm, Pb = Fb / Sb.

Fm / Sm = Fb / Sb.

Fb = Fm * Sb / Sm.

Fb = 10 N * 0.1 m2 / 0.0001 m2 = 10000 N.

Answer: in a hydraulic press, a force Fb = 10,000 N acts on the larger piston.

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