In a hydraulic press, a small piston with an area of 10 cm² is acted upon by a force of 100N.

In a hydraulic press, a small piston with an area of 10 cm² is acted upon by a force of 100N. What is the force on the larger 1m² piston?

Initial data: Sm (area of the small piston) = 10 cm2 (10 * 10-4 m2); Fm (force on the small piston) = 100 N; Sb (area of the larger piston) = 1 m2.

The force that acts on the larger piston of this hydraulic press is determined from the equality: P = Fm / Sm = Fb / Sb, whence Fb = Fm * Sb / Sm.

Calculation: Fb = 100 * 1 / (10 * 10-4) = 100 * 10 ^ 3 N (100 kN).

Answer:  A force of 100 kN acts on the larger piston.