In a hydraulic press, due to the action of the pump, a pressure of 0.7 MPa is created.

In a hydraulic press, due to the action of the pump, a pressure of 0.7 MPa is created. The diameter of the large piston is 50 cm. Find the force with which the large piston is.

Given:

P = 0.7 MPa is the pressure that is created in the hydraulic press;

D = 50 centimeters – the diameter of the large piston.

It is required to determine F (Newton) – the force acting on the larger piston.

Let’s convert the units of measurement to the SI system:

P = 0.7 MPa = 0.7 * 106 = 700000 Pascal.

D = 50 centimeters = 50/100 = 0.5 meters.

Find the surface area of ​​the large piston:

S = n * D ^ 2/4, where n = 3.14 is a geometric constant.

S = 3.14 * 0.5 ^ 2/4 = 3.14 * 0.25 / 4 = 0.785 / 4 = 0.2 m2 (the result has been rounded to one hundredth).

Then:

F = P * S = 700,000 * 0.2 = 140,000 Newtons.

Answer: A force equal to 140,000 Newtons acts on the large piston.