In a hydraulic press, the area of the small piston is 2 cm2, the large piston is 200 cm2.

In a hydraulic press, the area of the small piston is 2 cm2, the large piston is 200 cm2. The force of the small piston is 400N, the large one is 36kN. What is the strength gain?

The force ratio is F2 \ F1. Therefore, the gain in strength is: 36000N: 400N = 90
Answer: The strength gain is 90 N.



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