In a hydraulic press, the area of the small piston is 5 cm2, the area of the large one is 500 cm2.

In a hydraulic press, the area of the small piston is 5 cm2, the area of the large one is 500 cm2. The force acting on the small piston is 400 N, on the large one – 36 kN. What kind of strength gain does this press give? Why doesn’t the abs give the maximum (greatest) gain in strength? What gain in strength would this press have given in the absence of frictional force between the piston and the walls of the press?

Given: S1 = 5 cm2 = 0.0005 m2; S2 = 500 cm2 = 0.05 m2 F1 = 400 N; F2 = 36000 N Find: F2 / F1 -?; F2 ‘/ F’1-?

To calculate the payoff, we need to find the ratio:

F2 / F1 = 36000/400 = 90
The press does not give the maximum strength gain due to the frictional force.

If we imagine that there is no frictional force between the pistons and the walls of the vessel, then the equality is true:
F2 ‘/ F’1 = S2 / S1 = 0.05 / 0.0005 = 100
Answer: Taking into account the friction force, the win is 90, not taking into account its win is 100.