In a laboratory of 25 liters. acetylene was obtained 16 g of benzene. What is the percentage of the theoretically possible yield?

1. Let’s write down the reaction of obtaining benzene by trimerization of acetylene:

3C2H2 → C6H6;

2.Calculate the theoretical chemical amounts of acetylene and benzene:

ntheor (C2H2) = V (C2H2): Vm = 25: 22.4 = 1.116 mol;

ntheor (C6H6) = ntheor (C2H2): 3 = 1.116: 3 = 0.372 mol;

3.Calculate the practical amount of benzene:

ntract (C6H6) = m (C6H6): M (C6H6);

M (C6H6) = 6 * 12 + 6 = 78 g / mol;

ntract (C6H6) = 16: 78 = 0.205 mol;

4.determine the benzene yield:

ν (C6H6) = npract (C6H6): ntheor (C6H6) = 0.551 or 55.1%.

Answer: 55.1%.