In a lamp from a flashlight at a voltage of 3.5V, the current strength is 0.28A. Determinant of the resistance of the spiral lamp.

univerkov | December 8, 2020 | education

Given:
In a lamp from a flashlight at a voltage of 3.5V, the current strength is 0.28A.
R = U: I-Ohm’s Law.
R = 3.5V: 0.28A = 12.5Ω
Answer: resistance (R) = 12.5 ohms.

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