In a liquid with what density will an Archimedean force of 120 N act on a body weighing

In a liquid with what density will an Archimedean force of 120 N act on a body weighing 20 kg and a volume of 10 liters?

Given:

m = 20 kg

V = 10 l = 0.01 m ^ 3 (since a liter is 1000 times less than m ^ 3)

Fa = 120 N

Solution:

The force of Archimedes is the force with which a liquid pushes solids out of itself.

It is found by the formula Fа = p * g * V, where p is the density of the liquid, g is the acceleration of gravity of the planet (on earth it is ~ 9.8 N / kg, but it can be rounded up to 10 N / kg), and V is the volume of the part of the object that is immersed in the liquid.

You can immediately deduce the formula for finding p, or substitute our data and solve it as an equation.

Method 1: p = Fa / (g * V), substitute our data and calculate. p = 120 N / (10 N / kg * 0.01 m ^ 3) = 120 / 0.1 = 1200 kg / m ^ 3.

Method 2: 120 N = p * 10 N / kg * 0.01 m ^ 3; 0.1 * p = 120; p = 1200 kg / m ^ 3

In both methods, the answer is the same.

Answer: 1200 kg / m ^ 3