In a magnetic field with an induction of 1.2 T. At an angle of 30 degrees. a conductor with a length of 0.4 m

In a magnetic field with an induction of 1.2 T. At an angle of 30 degrees. a conductor with a length of 0.4 m moves towards the vector. It induces an emf of 2.4 v. Determine the speed of the conductor.

Given:
E = 2.4 in;
B = 1.2 T;
L = 0.4 m;
Angle equal to 30 degrees.
Decision:
We use the formula.
E = BLV * Sin a
Express the speed and get V = E / (BL * Sin a)
Substitute the known values:
V = 2.4 / 1.2 * 0.4 * 0.5 = 10 m / s
Answer: 10