# In a microwave oven, 0.5 l of sunflower oil is heated by 30 degrees in 2 minutes. what is the capacity

**In a microwave oven, 0.5 l of sunflower oil is heated by 30 degrees in 2 minutes. what is the capacity of this furnace if its efficiency is 80%? oil density 900 kg / m3, specific heat 1700 J / kg * С**

To find the power of the microwave oven under consideration, we will use the formula: η = Ap / Azatr = Cpm * m * Δt / (P * t) = Cpm * ρpm * V * Δt / (P * t), whence we express: P = Cpm * ρpm * V * Δt / (η * t).

Const: Cпм – beats. heat capacity of sunflower oil (Cпм = 1700 J / (kg * ºС)); ρпм – density of sunflower oil (ρпм = 900 kg / m3).

Data: V is the volume of heated sunflower oil (V = 0.5 l = 0.5 * 10-3 m3); Δt – change in oil temperature (Δt = 30 ºС); η is the efficiency of the considered microwave oven (η = 80% = 0.8); t – heating time (t = 2 min = 120 s).

Calculation: P = Cpm * ρpm * V * Δt / (η * t) = 1700 * 900 * 0.5 * 10-3 * 30 / (0.8 * 120) ≈ 239.1 W.

Answer: The power of the microwave oven in question is 239.1 watts.