In a mine at a depth of 100 m, 4.5 m3 arrives every minute. How much power is required for a pump to pump water to the surface?

These tasks: h (depth of the considered mine) = 100 m; t (time during which water arrives) = 1 min (in SI t = 60 s); V (volume of incoming water) = 4.5 m3.

Reference data: ρw (density of incoming water) = 1000 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.

The required pump power can be determined by the formula: N = A / t = ΔEp / t = m * g * h / t = V * ρw * g * h / t.

Let’s perform the calculation: N = A / t = ΔEp / t = m * g * h / t = 4.5 * 1000 * 10 * 100/60 = 75 * 10 ^ 3 = 75 kW.