In a parallelogram ABCD, BH is the height. If AB = 4, BC = 5 and cosABH = 0.6, then the parallelogram area is …

univerkov | May 31, 2021 | education

Let the angle ABН = X0, then the angle ABC = ABН + СВН = (90 + X) 0.

Sin (90 + X) = CosX.

Then SinABC = CosABH = 0.6.

Savsd = AB * BC * SinABC = 4 * 5 * 0.6 = 12 cm2.

Answer: The area of the parallelogram is 12 cm2.

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