In a parallelogram of ABCD bisectaris AK, equal to 4cm, divides the side of BC on bk and kc

In a parallelogram of ABCD bisectaris AK, equal to 4cm, divides the side of BC on bk and kc segments, each of which is 5 cm. What is the perimeter of the parallelogram?

Since AK bissectrice angle, then the angle of ВAK = Duck. The angle of the ВKA = DAK as an increase in the underlying angles when crossing parallel direct blood pressure and Sun part of AK, therefore, the AВK triangle is a free, Av = ВK.

Since, by condition, ВK = kc = 5 cm, then Av = sd = 5 cm.

Length of the segment Sun = ВK + ks = 5 + 5 = 10 cm.

Then the perimeter parallelogram will be equal to: Ravd = 2 * (AВ + Sun) = 2 * (5 + 10) = 30 cm.

Answer: The perimeter of the parallelogram is 30 cm.