In a parallelogram, the angle between the heights drawn from the top of the acute angle

In a parallelogram, the angle between the heights drawn from the top of the acute angle is 112.5 degrees. The magnitude of this acute angle is.

The heights of the parallelogram form right angles AKС and AHC.

In a convex quadrilateral AKСH, the sum of internal angles is 360, then the angle KCH = (360 – AKС – KAH – AHC) = (360 – 90 – 112.5 – 90) = 67.5.

In a parallelogram, the opposite angles are equal, then the angle BAD = BCD = KCH = 67.5.

Answer: The magnitude of the acute angle is 67.5.



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