In a plastic cup containing 150 g of hot tea at a temperature of 90 degrees
| February 9, 2021 | education
In a plastic cup containing 150 g of hot tea at a temperature of 90 degrees, a cold steel spoon weighing 50 g and with a temperature of 20 degrees was lowered. specific heat of tea …
Given: m1 (mass of tea in a cup) = 150 g (0.15 kg); t1 (tea temperature) = 90 ºС; m2 (weight of a steel spoon) = 50 g (0.05 kg); t2 (spoon temperature) = 20 ºС.
Reference values: C1 (specific heat capacity of tea, water) = 4200 J / (kg * K); C2 (specific heat capacity of steel) = 460 J / (kg * K).
The steady-state temperature is calculated from the equality: C1 * m1 * (t1 – tу) = С2 * m2 * (tу – t2).
4200 * 0.15 * (90 – tу) = 460 * 0.05 * (tу – 20).
56700 – 630tу = 23tу – 460.
653tу = 57160.
tу = 57160/653 = 87.53 ºС.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
