In a quadrilateral ABCD AB = CD, angle BAC = angle ACD, AC = 7cm AD = 6cm, AB = 4cm
In a quadrilateral ABCD AB = CD, angle BAC = angle ACD, AC = 7cm AD = 6cm, AB = 4cm which is equal to the perimeter of triangle ABC.
The solution of the problem:
Given a quadrangle in the problem statement, let this quadrilateral be the trapezoid ABCD. From angle A to angle C we draw a diagonal AC, which is equal to 7 cm. From the condition of the problem, the formed angle BAC is equal to the angle ACD. That is, the side AD is equal to the side BC, since an equal side lies in the triangle opposite an equal angle. The perimeter of the triangle is equal to the sum of all We know all sides of the triangle ABC.
1.Let’s find what the perimeter of the triangle ABC is equal to.
7 + 4 + 6 = 17 centimeters.
Answer: the perimeter of the triangle is 17 cm.