In a quadrilateral ABCD AB = CD, BC = AD. Prove that angle DA = angle DC and angle DB = angle DD.

We draw a quadrilateral AВСD and mark on it that AB = СD and BC = AD. Then we draw the ВD diagonal so that we have two triangles:  АВD and ВСD. Solution: 1) Consider triangles: AB = CD (by condition), BP = BC (by condition), BD-general. => triangles are equal (according to the third sign of equality of triangles)



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