In a rectangle ABCD AC18cm, AB = 17cm, O is the intersection point of the diagonals.

In a rectangle ABCD AC18cm, AB = 17cm, O is the intersection point of the diagonals. Find the perimeter of the triangle COD.

A rectangle is a quadrangle in which opposite sides are equal and the corners are right:

AB = CD = 17 cm.

BC = AD.

The diagonals of the rectangle are:

AC = BD = 18 cm.

They intersect at point O, and the intersection point is halved:

AO = OС = AC / 2;

AO = OС = 18/2 = 9 cm;

BO = OD = BD / 2;

ВO = OD = 18/2 = 9 cm.

Consider a triangle ΔСОD.

The perimeter of a triangle is the sum of all its sides:

PCOD = CO + OD + CD;

RСOD = 9 + 9 + 17 = 35 cm.

Answer: the perimeter of the triangle ΔСОD is 35 cm.