In a rectangle, the angle between the diagonals is 136 degrees.

In a rectangle, the angle between the diagonals is 136 degrees. Find the angle between the diagonal and the smaller side of the rectangle.

Since the diagonals of a rectangle are equal, and at the intersection point they are divided in half, the triangles formed when the diagonals intersect are isosceles.

In a triangle opposite the larger angle, the larger base will lie, then the larger base will lie opposite the angle 136.

In the triangle BОС, the angle ОВС = OCB = (180 – 136) / 2 = 44/2 = 22.

Then the angle ABO = BAO = 90 – 22 = 68.

Answer: The angle between the diagonal and the smaller base is 68.