In a rectangle, the angle between the diagonals is 82 degrees, the angles that form diagonals with the sides of the rectangle.

Since the diagonals of the rectangle are equal, and at the intersection point they are divided in half, the halves of the diagonals with the sides of the rectangle form four isosceles triangles.
Then, in the triangle AOB, the angle OBA = OAB = (180 – 82) / 2 = 49.
Then the angle СВO = DAO = 90 – 49 = 41.
Answer: The diagonals form angles 41 and 49 with the sides.



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