In a rectangle, the point of intersection of the diagonals is 4 cm farther from the smaller side than

In a rectangle, the point of intersection of the diagonals is 4 cm farther from the smaller side than from the larger side. The perimeter of the rectangle is 56 cm. Find its sides.

The solution of the problem:
1. The distance from the point of intersection of the diagonals in the rectangle to its larger side is x cm.
2. The distance from the point of intersection of the diagonals in the rectangle to its smaller side is (x + 4) cm.
3. Find out what is one side of the rectangle.
x * 2 = 2x cm.
4. Let’s calculate what is the other side of the rectangle.
2 * (x + 4) = (2x + 8) cm.
5. Let’s compose and solve the equation.
2x * 2 + 2 * (2x + 8) = 56;
4x + 4x + 16 = 56;
4x + 4x = 56 – 16;
8x = 40;
x = 40/8;
x = 5;
Answer: One side of the rectangle is 2 * x = 2 * 5 = 10 cm. The other side is 2 * x + 8 = 2 * 5 + 8 = 18 cm.