In a rectangular parallelepiped at the base of which the square lies, the lateral surface area is 22, total 30

In a rectangular parallelepiped at the base of which the square lies, the lateral surface area is 22, total 30. find the parallelepiped’s height.

Knowing the total surface area and side area, we determine the base area.

S floor = 2 * S main + S side.

Sb = (S floor – S side) / 2 = (30 – 22) / 2 = 8/2 = 4 cm2.

Since there is a square at the base of the parallelepiped, the length of its side is: AB = √Sbasn = √4 = 2 cm.

The lateral surface area is: Sbok = Rosn * AA1.

AA1 = S side / Rosn = 22/8 = 2.75 cm.

Answer: The height of the parallelepiped is 2.75 cm.



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