In a rectangular trapezoid ABCD, the diagonal AC is perpendicular to the side CD BC = 9

In a rectangular trapezoid ABCD, the diagonal AC is perpendicular to the side CD BC = 9 AC = 15 AD = 25 find the area of the trapezoid.

From the top of the obtuse angle of the trapezoid, we lower the height CH.

Quadrangle ABCH is a rectangle, then side AH = BC = 9 cm.

In a right-angled triangle ACH, according to the Pythagorean theorem, we determine the length of the leg CH.

CH ^ 2 = AC ^ 2 – AH ^ 2 = 15 ^ 2 – 9 ^ 2 = 225 – 81 = 144.

CH = 12 cm.

Determine the area of the trapezoid.

Savsd = (AD + BC) * CH / 2 = (25 + 9) * 12/2 = 204 cm2.

Answer: The area of the trapezoid is 204 cm2.



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