In a rectangular trapezoid ABCD, the large side AB is 25 and the base is 2 and 26, find the area of the trapezoid.

From the top of the trapezoid, draw the height CH.

Since the trapezoid is rectangular, and CH is height, then the quadrangle ABCH is a rectangle, then AH = BC = 2 cm.

The SDN triangle is rectangular, with the leg DH = AD – AH = 26 – 2 = 24 cm.

Then, by the Pythagorean theorem, CH ^ 2 = CD ^ 2 – DH ^ 2 = 625 – 576 = 49.

CH = 7 cm.

Then S avsd = (BC + AD) * CH / 2 = (2 + 26) * 7/2 = 98 cm2.

Answer: The area of the trapezoid is 98 cm2.



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