In a rectangular trapezoid, the base is 7 cm and 11 cm, the large lateral side makes an angle of 45

In a rectangular trapezoid, the base is 7 cm and 11 cm, the large lateral side makes an angle of 45 degrees with the base. find s trapezoid.

Let’s draw from the top С the height СН. Then in the right-angled triangle СDН the angle DСН = 180 – 90 – 45 = 45. Since the angles at the base of the triangle are equal, the triangle СDН is isosceles, СН = DH. Since ABCH is a rectangle, then AH = BC = 7 cm, then DH = CH = AD – AH = 11 – 7 = 4 cm.

Determine the area of the trapezoid.

Savsd = (ВС + АD) * СН / 2 = (7 + 11) * 4/2 = 36 cm2.

Answer: The area of the trapezoid is 36 cm2.



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