In a rectangular trapezoid, the bases are 22 cm and 6 cm, and the large side is 20 cm, find the smaller side.

In trapezoid ABCD, we will build the height of CH.

Since the trapezoid is rectangular, and CH is the height of the trapezoid, then the quadrangle ABCH is a rectangle, and therefore AH = BC = 6 cm.

Then DH = AD – AH = 22 – 6 = 16 cm.

The triangle CDH is rectangular, in which, according to the Pythagorean theorem, CH ^ 2 = CD ^ 2 – DH ^ 2 = 400 – 256 = 144.

CH = 12 cm.

Then AB = CH = 12 cm.

Answer: The smaller side is 12 cm.



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