In a rectangular trapezoid, the bases are 6 cm and 11 cm, the smaller side is 4 cm.

In a rectangular trapezoid, the bases are 6 cm and 11 cm, the smaller side is 4 cm.Find the sine cosine and tanges of the acute angle of the trapezoid

Let’s draw the height of the CH trapezoid. Quadrangle ABCH is a rectangle, since the trapezoid is rectangular, and CH is height. Then AH = BC = 6 cm, CH = AB = 4 cm.

The length of the segment DH = AD – AH = 11 – 6 = 5 cm.

From the right-angled triangle СDН we determine the length of the hypotenuse СD.

CD ^ 2 = CH ^ 2 + DH ^ 2 = 16 + 25 = 41.

СD = √41 cm.

Determine tg, Cos and Sin of the ADC angle.

tgD = CH / DH = 4/5.

CosD = DH / CD = 5 / √41.

SinD = CH / CD = 4 / √41.

Answer: tgD = 4/5, CosD = 5 / √41, SinD = 4 / √41.



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