In a rectangular trapezoid, the sides are 7 and 25 cm, and the smaller base is 2 cm.

Let’s build the height of the CH trapezoid ABCD.

Since the trapezoid is rectangular, and CH is its height, then the quadrangle ABCH is a rectangle, then BC = AH = 2 cm, CH = AB = 7 cm.

The triangle CDH is rectangular, then, according to the Pythagorean theorem, DH ^ 2 = CD ^ 2 – CH ^ 2 = 625 – 47 = 576.

DН = 24 cm.

Base length АD = АН + DH = 2 + 24 = 26 cm.

Determine the area of the trapezoid.

Savd = (ВС + АD) * СН / 2 = (2 + 26) * 7/2 = 98 cm2.

Answer: The area of the trapezoid is 98 cm2.



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