In a rectangular trapezoid, the sides are 7cm and 25cm and the smaller base is 2cm, find the area of the trapezoid.

From the top of the trapezoid, draw the height CH. The quadrilateral ABCN is rectangular, since CH is the height, and the trapezoid ABCD is rectangular, then CH = AB = 7 cm, AH = BC = 2 cm.

In a right-angled triangle BCH, we determine the length of the leg DH.

DH ^ 2 = CD ^ 2 – CH ^ 2 = 25 ^ 2 – 7 ^ 2 = 625 – 49 = 576.

DН = 24 cm.

Then the length of the base АD = АН + DH = 2 + 24 = 26 cm.

Determine the area of the trapezoid.

Savsd = (ВС + АD) * СН / 2 = (2 + 26) * 7/2 = 98 cm2.

Answer: The area of the trapezoid is 98 cm2.



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