In a rectangular trapezoid, the smaller lateral side AB = 10, the angle CDA = 45 degrees.

In a rectangular trapezoid, the smaller lateral side AB = 10, the angle CDA = 45 degrees. Find the distance from the vertex C to line AD.

The distance from point C to the base of AD is the perpendicular CH to this base.

Since the trapezoid is rectangular, AB is perpendicular to BC and AD, and since СН is perpendicular to them, the quadrilateral ABCH is a rectangle.

Then CH = AB = 10 cm.

Answer: The distance from summit C to AD is 10 cm.



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