In a rectangular trapezoid, the sum of the angles with a smaller base = 248 find the corners of the trapezoid

Since the trapezoid is rectangular, the angle ABC = BAD = 90.

By condition, the sum of the angles (ABC + BCD) = 248.

90 + BCD = 248.

Angle ВСD = 248 – 90 = 158.

Since the sum of the angles at the side of the trapezoid is 180, the angle ADC = 180 – BCD = 180 – 158 = 22.

Answer: The angles of the trapezoid are 90, 90, 158, 22.



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