In a rectangular triangle ABC (C = 90 °), CD and AE bisectors intersect at point O.
| June 28, 2021 | education
In a rectangular triangle ABC (C = 90 °), CD and AE bisectors intersect at point O. AOC angle value is 115 °. Find it a smaller acute angle of the ABC triangle.
Bissectrix CD is a bisector of a direct angle, then the angle of ACD = ASO = 90/2 = 45.
In the AOC triangle, we define the value of the CAO angle.
The angle of saa = (180 – AOC – ACO) = (180 – 115 – 45) = 20.
Ae bisector angle of you, then the angle of you = 2 * saa = 2 * 20 = 40.
Then the angle of ABC = (90 – 40) = 60.
Answer: A smaller sharp angle is 60.
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