In a regular quadrangular pyramid SABSD with a height SO = √2 and a side edge SA = 2 find the base side AB
| September 9, 2021 | education
Since SO is the height, then the triangle SOA is a rectangle, we find the side OA, by the Pythagorean theorem we get:
OA = √ (2 + 4) = √6.
Since the pyramid is regular, at its base lies a square, the side of which can also be found by the Pythagorean theorem:
AB = √ (6 + 6) = √12 = 2√3.
Answer: the required side of the base of the pyramid is 2√3.
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