In a regular quadrangular pyramid, the edge is 2 cm, find the total surface area of the pyramid.

univerkov | September 6, 2021 | education

The side faces of the pyramid are equilateral triangles with a side of 2 cm, then the height SН of the triangle SСD will be: SH = СD * √3 / 2 = 2 * √3 / 2 = √3 cm.

Then Ssd = C * SH / 2 = 2 * √3 / 2 = √3 cm2.

The lateral surface area will be equal to: Sside = 4 * Ssd = 4 * √3 cm2.

There is a square at the base of the pyramid, then Sosn = CD ^ 2 = 4 cm2.

Then Spov = Sbok + Sbn = 4 * √3 + 4 = 4 * (√3 + 1) cm2.

Answer: The total surface area is 4 * (√3 + 1) cm2.

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