In a regular quadrangular pyramid, the height is 12 cm, and the height of the side edge is 15 cm. Find the side edge.

The height of the side face and the height of the pyramid form a right-angled triangle HOM.

Then, by the Pythagorean theorem, OH ^ 2 = MH ^ 2 – MO ^ 2 = 225 – 144 = 81. OH = 9 cm.

The side faces of the pyramid are equilateral triangles, then the height of MH is its median, and then DH = CH.

In the right-angled triangle COH, the acute angles are 45, then the triangle COH is rectangular and isosceles, OH = CH = 9 cm.

In a right-angled triangle MCH, according to the Pythagorean theorem, we determine the length of the hypotenuse MC.

MC ^ 2 = MH ^ 2 + CH ^ 2 = 225 + 81 = 306.

MC = √306 = 3 * √34 cm2.

Answer: The length of the side rib is 3 * √34 cm2.



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