In a regular quadrangular pyramid, the height is 12 cm, and the height of the side edge is 15 cm. Find the side edge.

The height of the side face, the height of the pyramid and the OH segment form a right-angled triangle RON. Then, by the Pythagorean theorem, OH ^ 2 = PH ^ 2 – OP ^ 2 = 225 – 144 = 81.

OH = √81 = 9 cm.

Since point O is the middle of AC, point H is the middle of BC, then OH is the middle line of triangle ABC, then AB = 2 * OH = 2 * 9 = 18 cm.

Let us determine the length of the AC diagonal of the AВСD square.

AC ^ 2 = 2 * AB ^ 2 = 2 * 324 = 648.

AC = √648 = 18 * √2.

Then OС = 18 * √2 / 2 = 9 * √2 cm.

In a right-angled triangle POC, by the Pythagorean theorem, we determine the length of the hypotenuse PC.

PC ^ 2 = PO ^ 2 + OС ^ 2 = 144 + 162 = 306.

РС = √306 = 3 * √34 cm.

Answer: The length of the side is 3 * √34 cm.



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