In a regular quadrangular pyramid, the length of the side of the base is 14 cm

In a regular quadrangular pyramid, the length of the side of the base is 14 cm, and the length of the side edge is 10 cm. Find the area of the diagonal section.

In order to solve this problem, know the formulas for calculating the required elements.

D = √ (2 * a²) = a√2 = 14√2 (cm).

0.5 * D = 7√2 square base. H = √ (p² – (0.5 * D) ²) = √ (100 – 49 * 2) = √2 (cm).

Now the area of the diagonal section is:

S = 0.5 * 14√2 * √2 = 14 (cm²).

Therefore our answer is 14 cm².