In a regular triangle FKL, heights are drawn from the vertices F and K, which intersect at point O.

In a regular triangle FKL, heights are drawn from the vertices F and K, which intersect at point O. Find the degree measure of the acute angle formed by these heights.

In an equilateral triangle of the height of the triangle, there are also bisectors of the angles at the vertices. Then the angle OFB = 60/2 = 30.

Triangle FOB is rectangular, then angle FOB = 90 – 30 = 60, angle AOB = 180 – 60 = 120.

Answer: The angles at the intersection of heights are 60 and 120.



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