In a regular triangular pyramid, the lateral edge is 5 comma, the tangent of the angle between the lateral
In a regular triangular pyramid, the lateral edge is 5 comma, the tangent of the angle between the lateral face and the plane of the base is 0.25√11 find the side of the base of the pyramid.
Since an equilateral triangle lies at the base of the pyramid, then AO / OH = 2/1.
Let the length of the segment OH = X cm, then AO = 2 * X cm.
In a right-angled triangle AOD, according to the Pythagorean theorem, DO ^ 2 = AD ^ 2 – AO ^ 2 = 25 – 4 * X2. (one).
In a right-angled triangle DOH, tgH = DО / ОН.
DO = OH * tgH = X * √11 / 4.
Then DO ^ 2 = X ^ 2 * 11 / 16. (2).
Equate Equations 1 and 2.
25 – 4 * X ^ 2 = 11 * X ^ 2/16.
75 * X ^ 2/16 = 25.
X ^ 2 = 25 * 16/75
X = 20/5 * √3 = 4 / √3 cm
AO = 8 / √3.
AH = 4 / √3 + 8 / √3 = 12 / √3 = 4 * √3 cm.
AH = BC * √3 / 2.
BC = 2 * AH / √3 = 2 * 4 * √3 / √3 = 8 cm.
Answer: The side of the base of the pyramid is 8 cm.