In a resistor with a resistance of 360 ohms at a voltage of 15 V, a work of 450 J

In a resistor with a resistance of 360 ohms at a voltage of 15 V, a work of 450 J was performed with an electric current. How long did the work take?

To find out the duration of the resistor taken, we will use the formula: Q = A = U ^ 2 * t / R, whence we express: t = R * Q / U ^ 2.

Data: R – resistance (R = 360 Ohm); A – work perfect by current (A = 450 J); U – operating voltage (U = 15 V).

Let’s make a calculation: t = R * Q / U ^ 2 = 360 * 450/15 ^ 2 = 720 s (12 minutes).

Answer: The work of 450 J was supposed to be done by the current in 12 minutes.