In a rhombus ABCD, angle D = 140 degrees. Determine the angles of the triangle AOD.

In a rhombus ABCD, angle D = 140 degrees. Determine the angles of the triangle AOD. O is the intersection point of the diogonals.

Since the diagonals of the rhombus divide the angle at the apex in half, then the angle ADO = ADC / 2 = 140/2 = 70.

The diagonals of the rhombus intersect at right angles, then the angle AOD = 90.

The sum of the angles of the triangle is 180, then the angle OAD = 180 – AOD – ADO = 180 – 90 – 70 = 20.

Answer: The angles of triangle AOD are equal to 20, 70, 90.



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