In a rhombus ABCD, BAO = 56 degrees, where O is the intersection point of the diagonals
| August 16, 2021 | education
In a rhombus ABCD, BAO = 56 degrees, where O is the intersection point of the diagonals of the rhombus. Find all the corners of the rhombus.
The diagonals of the rhombus divide the angle at the vertex in half, then the angle MAO = BAO = 56, then the angle BAM = 2 * BAO = 2 * 56 = 112.
The sum of the adjacent angles of the rhombus is 180, then the angle ABC = 180 – BAM = 180 – 112 = 68.
Since the rhombus has the opposite angles of the rhombus, the angle AMC = ABC = 68, the angle BCM = BAM = 112.
Answer: The angles of the rhombus are 68, 112, 68, 112.
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