In a rhombus, one of the diagonals is equal to the side. Find the corners of the rhombus.

Let the diagonal BD = AB = AD = CD = CB, then the triangle ABD is equilateral. In an equilateral triangle, all angles are 60, then the angle BAD = ABD = ADB = 60. The diagonal of the rhombus divides the angle at the apex in half, then the angle ABC = 2 * ABD = 2 * 60 = 120.

The opposite angles of the rhombus are equal, then the angle BAD = BCD = 60, the angle ABC = ADC = 120.

Answer: The angles of the rhombus are 60 and 120.



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