In a right-angled triangle ∆ABS ∠C = 90 °, ∠A = 30 °, AB = 16 cm.Find the distance from point B to line AC.
| August 5, 2021 | education
The shortest distance from the vertex B to the side of CA is the perpendicular BC, and since the angle ABC = 90, this distance is the leg CB.
The BC leg is located opposite an angle of 300, then its length is equal to half the length of the AC hypotenuse.
BC = AB / 2 = 16/2 = 8 cm.
Answer: The distance from point B to line AC is 8 cm.
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