In a right-angled triangle A BC, an angle C of a straight line is a bisector BD. Find the angles

In a right-angled triangle A BC, an angle C of a straight line is a bisector BD. Find the angles of triangle ABD if the angle CBD is 20 degrees.

Since, according to the condition, the segment BD is the bisector of angle B, then the angle ABD = CBD = 20, then the angle ABC = ABD + CBD = 20 + 20 = 40.

Angle ACB = 90, then angle BAC = 180 – ACB – ABC = 180 – 90 – 40 = 50.

Answer: The angles of the triangle ABC are 40, 50, 90.



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